Скачать с ютуб 995. Minimum Number of K Consecutive Bit Flips || LeetCode POTD || Explained in HINDI в хорошем качестве

995. Minimum Number of K Consecutive Bit Flips || LeetCode POTD || Explained in HINDI

Instagram link:-   / reelcoding      / @reelcoding   Approach 1:- Initialization: We initialize the variables n length of the array, ans to store the number of flips, times to track the number of times a flip has occurred, and an array flipped to mark the indices where flips have been performed. Iterating through the array: For each element in the array, we check if the current index i is greater than or equal to k. If so, we adjust times by subtracting the value at flipped of i - k to account for flips that are no longer affecting the current position. Checking conditions for flipping: We check if the current element needs to be flipped: If the current element is 1 and the times is odd, it means it needs to be flipped. If the current element is 0 and the times is even, it means it needs to be flipped. If the current element needs to be flipped, we: Check if flipping k bits from the current index exceeds the array bounds. If so, return -1. Increment ans and times, and mark the current index in the flipped array. Returning the result: After processing all elements, return the value of ans which represents the minimum number of k-bit flips needed. Time and Space Complexity Time Complexity: O of n We iterate through the array once, performing constant time operations for each element. Space Complexity: O of n We use an auxiliary array flipped of size n to keep track of flip operations. Approach 2:- Initialization: We initialize n as the length of the input array nums, ans to store the number of flips, and times to keep track of the number of times flips have occurred. Iterating through the array: We iterate through the array using a for loop. Adjusting times for elements that are out of the k-flip range: For indices i greater than equal to k, we check if nums of i - k has been flipped indicated by nums of i - k greater than 1. If so, we decrement the flip effect and adjust times accordingly. Checking conditions for flipping: We determine if the current element needs to be flipped based on its value and the current flip count: If nums of i is 1 and times is odd, it needs to be flipped. If nums of i is 0 and times is even, it needs to be flipped. If a flip is needed and flipping k bits from the current index exceeds the array bounds, return -1. Otherwise, we increment ans and times, and mark the current index by adding 2 to nums of i. Returning the result: After processing all elements, return ans, which represents the minimum number of k-bit flips needed. Time and Space Complexity Time Complexity: O(n) We iterate through the array once, performing constant time operations for each element. Space Complexity: O(1) We use only a few extra variables and modify the input array in place. Whether you're new to problem-solving or seeking insights into Java programming techniques, this video offers valuable insights into tackling similar challenges effectively. Do join with me guys for daily problem solving on LeetCode. Please like and subscribe this channel and share among your friends, it helps me to motivate and bring more videos for you guys. ❤️❤️ Soon, DSA batch (Hinglish) is going to launch on this channel. So, do subscribe so that you will get the notification for all new videos.👍👍🔔🔔. Do comment if any doubts left. Thank you 😊 #leetcode #computerscience #leetcodesolutions #leetcodequestionandanswers #code #learning #dsalgo #dsa #CodingExplanation #AlgorithmTutorial #JavaProgramming #DataStructures #DynamicProgramming #CodeExplanation #ProgrammingTutorial #AlgorithmExplanation #TechTutorial #LearnToCode #ProblemSolving #ProgrammingConcepts #SoftwareDevelopment #TechEducation #CodingCommunity #CodeBreakdown #ComputerScience #JavaTutorial #AlgorithmAnalysis #EducationalContent 995. Minimum Number of K Consecutive Bit Flips Leetcode 995 Minimum Number of K Consecutive Bit Flips Leetcode daily challenge Leetcode potd 995 Minimum Number of K Consecutive Bit Flips leetcode potd today solution leetcode potd today leetcode grind leetcode questions for interview leetcode series leetcode hindi