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Whatsapp Community Link : https://www.whatsapp.com/channel/0029... This is the 18th Video of our Playlist "Heap : Popular Interview Problems" by codestorywithMIK In this video we will try to solve a good Heap problem : IPO | Easy Beginner Friendly | Story To Code | Leetcode 502 | codestorywithMIK I will explain the intuition so easily that you will never forget and start seeing this as cakewalk EASYYY. We will do live coding after explanation and see if we are able to pass all the test cases. Also, please note that my Github solution link below contains both C++ as well as JAVA code. Problem Name : IPO | Easy Beginner Friendly | Story To Code | Leetcode 502 | codestorywithMIK Company Tags : MICROSOFT My solutions on Github(C++ & JAVA) : https://github.com/MAZHARMIK/Intervie... Leetcode Link : https://leetcode.com/problems/ipo/des... My DP Concepts Playlist : • Roadmap for DP | How to Start DP ? | ... My Graph Concepts Playlist : • Graph Concepts & Qns - 1 : Graph will... My Recursion Concepts Playlist : • Introduction | Recursion Concepts And... My GitHub Repo for interview preparation : https://github.com/MAZHARMIK/Intervie... Instagram : / codestorywithmik Facebook : / 100090524295846 Twitter : / cswithmik Subscribe to my channel : / @codestorywithmik ╔═╦╗╔╦╗╔═╦═╦╦╦╦╗╔═╗ ║╚╣║║║╚╣╚╣╔╣╔╣║╚╣═╣ ╠╗║╚╝║║╠╗║╚╣║║║║║═╣ ╚═╩══╩═╩═╩═╩╝╚╩═╩═╝ Summary : The problem is to maximize the capital w after undertaking up to k projects, where each project has a specific profit and requires a certain amount of initial capital. Steps: Data Preparation: Create a list of projects where each project is represented as a pair of capital and profit. Sorting: Sort the list of projects based on the required capital in ascending order. This allows us to efficiently access the projects that can be undertaken with the available capital. Max Heap: Use a max heap (priority queue) to keep track of the profits of the projects that can currently be undertaken (i.e., projects whose capital requirement is less than or equal to the current capital w). Iterative Selection: Iterate up to k times, in each iteration: Add all projects that can be undertaken with the current capital to the max heap. If the max heap is empty, break out of the loop as no more projects can be undertaken. Otherwise, extract the maximum profit from the heap and add it to the current capital w. This greedy approach ensures that at each step, the project with the maximum profit is chosen from the set of projects that can be undertaken, thus maximizing the capital efficiently. ✨ Timelines✨ 00:00 - Introduction #coding #helpajobseeker #easyrecipes #leetcode #leetcodequestionandanswers #leetcodesolution #leetcodedailychallenge #leetcodequestions #leetcodechallenge #hindi #india #coding #helpajobseeker #easyrecipes #leetcode #leetcodequestionandanswers #leetcodesolution #leetcodedailychallenge#leetcodequestions #leetcodechallenge #hindi #india #hindiexplanation #hindiexplained #easyexplaination #interview#interviewtips #interviewpreparation #interview_ds_algo #hinglish #github #design #data #google #video #instagram #facebook #leetcode #computerscience #leetcodesolutions #leetcodequestionandanswers #code #learning #dsalgo #dsa #newyear2024