Скачать с ютуб Minimum Number of Days to Make m Bouquets | Simple Thought Process| Leetcode 1482 | codestorywithMIK в хорошем качестве

Minimum Number of Days to Make m Bouquets | Simple Thought Process| Leetcode 1482 | codestorywithMIK

Whatsapp Community Link : https://www.whatsapp.com/channel/0029... This is the 29th Video of our Playlist "Binary Search : Popular Interview Problems" by codestorywithMIK In this video we will try to solve a very good and famous Problem on Binary Search on Answer topic : Minimum Number of Days to Make m Bouquets | Simple Thought Process | Leetcode 1482 | codestorywithMIK I will explain the intuition so easily that you will never forget and start seeing this as cakewalk EASYYY. We will do live coding after explanation and see if we are able to pass all the test cases. Also, please note that my Github solution link below contains both C++ as well as JAVA code. Problem Name : Minimum Number of Days to Make m Bouquets | Simple Thought Process | Leetcode 1482 | codestorywithMIK Company Tags : AMAZON My solutions on Github(C++ & JAVA) : https://github.com/MAZHARMIK/Intervie... Leetcode Link : https://leetcode.com/problems/minimum... My DP Concepts Playlist :    • Roadmap for DP | How to Start DP ? | ...   My Graph Concepts Playlist :    • Graph Concepts & Qns - 1 : Graph will...   My Recursion Concepts Playlist :    • Introduction | Recursion Concepts And...   My GitHub Repo for interview preparation : https://github.com/MAZHARMIK/Intervie... Instagram :   / codestorywithmik   Facebook :   / 100090524295846   Twitter :   / cswithmik   Subscribe to my channel :    / @codestorywithmik   ╔═╦╗╔╦╗╔═╦═╦╦╦╦╗╔═╗ ║╚╣║║║╚╣╚╣╔╣╔╣║╚╣═╣ ╠╗║╚╝║║╠╗║╚╣║║║║║═╣ ╚═╩══╩═╩═╩═╩╝╚╩═╩═╝ Summary : getNumOfBouquets Method: This method calculates how many bouquets can be made by the mid day. It iterates through bloomDay to count consecutive flowers that can be picked, forming bouquets when k consecutive flowers are found. minDays Method: This method uses binary search to find the minimum day (minDays) by which m bouquets can be made. It initializes startDay to 1 (assuming 0 is not a valid day) and endDay to the maximum value in bloomDay. In the binary search loop, it calculates mid and uses getNumOfBouquets to check if at least m bouquets can be made by mid day. If m bouquets can be made, it updates minDays and adjusts endDay to search for potentially smaller valid days. If not, it adjusts startDay to search for larger valid days. Edge Case Handling: If there are not enough flowers to make m bouquets, it returns -1 immediately. Usage The main method provides an example usage of the Solution class to test the minDays method. By following this structure, we ensure the solution remains efficient and easy to understand. ✨ Timelines✨ 00:00 - Introduction #coding #helpajobseeker #easyrecipes #leetcode #leetcodequestionandanswers #leetcodesolution #leetcodedailychallenge #leetcodequestions #leetcodechallenge #hindi #india #coding #helpajobseeker #easyrecipes #leetcode #leetcodequestionandanswers #leetcodesolution #leetcodedailychallenge#leetcodequestions #leetcodechallenge #hindi #india #hindiexplanation #hindiexplained #easyexplaination #interview#interviewtips #interviewpreparation #interview_ds_algo #hinglish #github #design #data #google #video #instagram #facebook #leetcode #computerscience #leetcodesolutions #leetcodequestionandanswers #code #learning #dsalgo #dsa #newyear2024